First slide

Friction on inclined plane of angle more than angle of repose

Question

A body of mass 10 kg is lying on a rough plane inclined at an angle of 30° to the horizontal and the coefficient of friction is 0.5. The minimum force required to pull the body up the plane is

Moderate

A

914 N
B

91.4 N
C

9.14 N
D

0.914 N

Solution

$\begin{array}{l} F = mg (\sin θ + μcos θ) \\ = 10 \times 9 .8 (\sin 30^{\circ} + 0 .5 \cos 30^{\circ}) = 91 .4 N \end{array}$

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