First slide

Work done by Diff type of forces

Question

A body of mass 300 kg is moved through 10m along a smooth inclined plane of angle 30⁰. The work done in
moving (in joules) is (Take, g = 9.8 ms^-2)

Moderate

A

4900
B

9800
C

14700
D

2450

Solution

Work done, $W = m g \sin θ \times s$
$= 300 \times 9.8 \times \sin 30 ° \times 10$
$= 300 \times 9.8 \times \frac{1}{2} \times 10 = 14700 J$

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