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Q.

A body of mass 2 kg moves down the quadrant of a circle of radius 4 m. The velocity on reaching the lowest point is 8 ms-1. Work done against friction is (take g = 10m/s2 )

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a

78.4 J

b

64 J

c

16 J

d

zero

answer is C.

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Detailed Solution

According to work energy theorem, work done by all forces  =ΔKEWgr+Wfr=ΔK.E=12mv2−0=12×2×64=64⇒Wfr=64−Wgr=64−mgR=64−80=−16JThus work done by body against friction = 16 J
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