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Q.

A body of mass 4kg is moving along positive X – direction with a velocity of 5ms−1 . Now a force of 202N  is applied at an angle 450  with X – axis. Its velocity after 3s  is,

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a

20ms−1

b

15ms−1

c

25ms−1

d

5ms−1

answer is C.

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Detailed Solution

Fx=202cos450=20N F=ma ⇒20=4a ⇒a=204=5m/s2Vx=5+204(3)=20 m/sVy=at=5(3)=15m/sV=Vx2+Vy2=25m/s
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A body of mass 4kg is moving along positive X – direction with a velocity of 5ms−1 . Now a force of 202N  is applied at an angle 450  with X – axis. Its velocity after 3s  is,