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Q.

A body of mass 10 kg is moving along a straight line with a linear momentum of 240 kgms−1 . If a constant force of 20 N acts for 5s opposite to direction of motion, the work done by the force during this time is

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a

1900 J

b

1440 J

c

1190 J

d

1200 J

answer is A.

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Detailed Solution

F×Δt=Pf−Pi                 −20×5=Pf−240⇒Pf=140       w=12m(Pf2−Pi2)=12×10[(140)2−(240)2]                 w=1900J
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A body of mass 10 kg is moving along a straight line with a linear momentum of 240 kgms−1 . If a constant force of 20 N acts for 5s opposite to direction of motion, the work done by the force during this time is