First slide

Second law

Question

A body of mass 3 kg is moving along a straight line with a velocity of 24ms^-1 . When it is at a point 'P' a force of 9 N acts on the body in a direction opposite to its motion. The time after which it will be at 'P' again is,

Moderate

A

8s
B

16s
C

12s
D

24s

Solution

When it reaches the point ‘P’ again S=0,
Using $a = \frac{F}{m}; S = ut + \frac{1}{2} {at}^{2}$

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