A body of mass 5 kg is moving with a momentum of 10 kg-m/s. A force of 0.2 N acts on it in the direction of motion of the body for 10 seconds. The increase in its kinetic energy is (in J)

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answer is 4.4.

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Detailed Solution

Change in momentum = Force × timeP2−P1=F×t=0.2×10=2⇒P2=2+P1=2+10=12kg-m/sIncrease in K.E. = 12m(P22−P12) =12×5(12)2−(10)2=4410=4.4J

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