Questions
A body of mass 5 kg is moving with a momentum of 10 kg-m/s. A force of 0.2 N acts on it in the direction of motion of the body for l0 seconds. The increase in its kinetic energy is
a
2.8 joules
b
3.2 joules
c
3.8 joules
d
4.4 joules
detailed solution
Correct option is D
Change in momentum = Force x timeP2-P1 = F ×t = 0.2×10 = 2⇒P2 = 2+P1 = 2+10 = 12 kg-m/sIncrease in K.E.= 12m(P22-P21) = 12×5[(12)2-(10)2]= 4410 = 4.4 JTalk to our academic expert!
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A light body A and a heavy body B have equal linear momentum. Then the KE of the body A is
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