A body of mass 5×103kg moving with speed 2 ms-1 collides with a stationary  body of mass 15×103 kg  inelastically and sticks to it. Then, loss in kinetic energy of the system will be [AIIMS 2019]

Given, mass of body,  m1= 5×103 kgVelocity, v1=2 ms-1and mass of another body, m2=15×103 kgFor perfectly inelastic collision, e = 0.∴ Loss in kinetic energy of system,                     ΔEK=12m1m2m1+m2×v12                              =12×5×103×15×1035×103+15×103×(2)2                              = 7.5×103J                               = 7.5 kJ