First slide

Collisions

Question

A body of mass 4 kg moving with velocity 12 m/s collides with another body of mass 6 kg at rest. If two bodies stick together after collision, then the loss of kinetic energy of system is

Moderate

A

Zero
B

288 J
C

172.8 J
D

144 J

Solution

Loss in K.E. = $\frac{m_{1} m_{2}}{2 (m_{1} + m_{2})} {(u_{1} - u_{2})}^{2}$
= $\frac{4 \times 6}{2 \times 10} \times {(12 - 0)}^{2}$ = 172.8 J

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