Questions
A body of mass 1kg is moving with velocity 30 ms-1due north. It is acted on by a force of 10N due east for 4 seconds. Find the velocity of the body after the force ceases to act
detailed solution
Correct option is C
V→y=30j^m/s V→x=101×4i^m/s=40i^m/s∴V=Vx2+Vy2=50m/s.Talk to our academic expert!
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Statement I : The familiar equation mg = R for a body on a table is true only if the body is in equilibrium.
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