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Q.

A body of mass 1kg is moving with velocity 30 ms-1due north. It is acted on by a force of 10N due east for 4 seconds. Find the velocity of the body after the force ceases to act

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a

302m/s

b

40 m/s

c

50 m/s

d

45 m/s

answer is C.

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Detailed Solution

V→y=30j^m/s V→x=101×4i^m/s=40i^m/s∴V=Vx2+Vy2=50m/s.
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