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A body of mass 2kg is moving with velocity 10 m/s towards east. Another body of same mass and same velocity moving towards north collides with former and coalesces and moves towards north-east. Its velocity is

10 m/s
5 m/s
2.5 m/s
52 m/s

detailed solution

Correct option is D

Initial momentum = P→=mvi^+mvj^ |P→|=2mvFinal momentum = 2m×VBy the law of conservation of momentum 2m×V=2 mv⇒V=v2In the problem v=10m​/​s  (given)  ∴V=102=52 m​/​s

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