A body of mass 2 kg is placed on a horizontal surface having kinetic friction 0.4 and static friction 0.5. If the force applied on the body is 2.5 N, then the frictional force acting on the body will be
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a
8 N
b
10 N
c
20 N
d
2.5 N
answer is D.
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Detailed Solution
fms = 0.5 ×2×10 N = 10 NSince the applied force is less than force of friction, therefore the force of friction is equal to the applied force i.e., 2.5 N
A body of mass 2 kg is placed on a horizontal surface having kinetic friction 0.4 and static friction 0.5. If the force applied on the body is 2.5 N, then the frictional force acting on the body will be