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Q.

A body of mass 2.0 kg is placed on a smooth horizontal surface. Two forces F1 = 20 N and F2 = 103 N are acting on the body in directions making angles of 30° and 60° to the surface. The reaction of the surface on the body will be

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a

20 N

b

25 N

c

5 N

d

zero

answer is D.

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Detailed Solution

Let us find vertical force: F1 sin 300 + F2 sin 600 = 20 ×12+103(32) = 25 NThis is greater than mg. So contact of body with surface will be lost and reaction will be zero.
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