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A body of mass 1 kg is projected with velocity 50 ms-1at an angle of 300 with the horizontal. At the highest point of its path, a force 10 N starts acting on body for 5 s vertically upward besides gravitational force. What is the horizontal range of the body? (Take, g = 10 ms-2)

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a

125 3m

b

200 3m

c

500 m

d

250 3m

answer is D.

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Detailed Solution

For 5 s, weight of the body is balanced by the given force. Hence, it will move in a straight line as shown in the figure.R=u2sin2θg+(ucosθ)t=(50)2·sin60°10+50×cos30°(5)=2503 m

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A body of mass 1 kg is projected with velocity 50 ms-1at an angle of 300 with the horizontal. At the highest point of its path, a force 10 N starts acting on body for 5 s vertically upward besides gravitational force. What is the horizontal range of the body? (Take, g = 10 ms-2)