A body of mass $$1$$ kg is projected with velocity $$50$$ $$ms-1at$$ an angle of $$300$$ with the horizontal. At the highest point of its path, a force $$10$$ N starts acting on body for $$5$$ s vertically upward besides gravitational force. What is the horizontal range of the body? (Take$$, g $$=$$ $$10$$ $$ms-2)

Question

A body of mass $$1$$ kg is projected with velocity $$50$$ $$ms-1at$$ an angle of $$300$$ with the horizontal. At the highest point of its path, a force $$10$$ N starts acting on body for $$5$$ s vertically upward besides gravitational force. What is the horizontal range of the body? (Take$$, g $$=$$ $$10$$ $$ms-2)

Infinity Learn · Accepted Answer

For $$5$$ s, weight of the body is balanced by the given force. Hence, it will move in a straight line as shown in the figure.$$R=u2sin2$$θ$$g+(ucos$$θ$$)t=(50)2$$·$$sin60$$°$$10+50$$×$$cos30$$°$$(5)=2503$$ m

A body of mass 1 kg is projected with velocity 50 ${ms}^{- 1}$ at an angle of 30⁰ with the horizontal. At the highest point of its path, a force 10 N starts acting on body for 5 s vertically upward besides gravitational force. What is the horizontal range of the body? (Take, g = 10 ${ms}^{- 2}$ )

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A body of mass 1 kg is projected with velocity 50 ms-1at an angle of 300 with the horizontal. At the highest point of its path, a force 10 N starts acting on body for 5 s vertically upward besides gravitational force. What is the horizontal range of the body? (Take, g = 10 ms-2)

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A body of mass 1 kg is projected with velocity 50 ${ms}^{- 1}$ at an angle of 30⁰ with the horizontal. At the highest point of its path, a force 10 N starts acting on body for 5 s vertically upward besides gravitational force. What is the horizontal range of the body? (Take, g = 10 ${ms}^{- 2}$ )