A body of mass 40 kg stands on a weighing machine in an accelerated lift. The reading on the scale of the weighing machine is 300 N. Find the magnitude and direction of acceleration.

Weighing machine reads less reading ⇒  apparent weight decrease, i.e lift is coming downwards with acceleration. R=m(g−a) 300=40(g−a) 7.5=g−a⇒a=9.8−7.5                                 =2.3ms−2