A body of mass 2kg is thrown up vertically with kinetic energy of 490J. If g = 9.8/ms2 , the height at which the kinetic energy of the body becomes half of the original value, is
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a
50m
b
25m
c
12.5m
d
19.6m
answer is C.
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Detailed Solution
At projection, T.E= K.E = 490 at given point, P.E'+K.E'=T.Emgh+K.E2=T.E