A body of mass 5 kg under the action of constant force F=Fxi^+Fyj^  has velocity at t=0s  as v→=(6i^−2j^)m/s  and at t=10s as v→=+6j^m/s . The force F→ is:

From question, Mass of body, m=5  kg Velocity at t=0,  u=(6i^−2j^)m/s Velocity at t=10s ,v=+6j^m/s Force, F=? Acceleration, a=v−ut =6j^−(6i^−2j^)10=−3i^+4j^5m/s2 Force, F=ma =5×(−3i^+4j^)5=(−3i^+4j^)N