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Q.

A body of mass 3 kg is under a force, which causes a displacement in it is given by S=t33 (in m). Find the work done by the force in first 2 seconds

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a

2 J

b

3.8 J

c

5.2 J

d

24 J

answer is D.

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Detailed Solution

S=t33∴dS=t2dta=d2Sdt2=d2dt2t33=2tm/s2Now work done by the force W=∫02 F⋅dS=∫02 ma⋅dS∫02 3×2t×t2dt=∫02 6t3dt=32t402=24J
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