A body of mass ‘m’ is attached to the lower end of a metal wire, whose upper end is fixed. If the elongation in the wire is ‘l ’, the correct choices of the following are a) Loss in potential energy of mass is mglb) Elastic potential energy stored in the wire is mgl2c) Elastic potential energy stored in the wire is mgld) Heat produced is mgl2
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a
a, c only
b
a,b,d
c
c,d only
d
a,c,d
answer is B.
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Detailed Solution
As the mass moved by ‘l’ loss in PE = mgl.Elastic PE = 12Fl = 12mglRemaining energy lost as heat energy