A body of mass ‘m’ is dropped and another body of mass M is projected vertically up with speed ‘u’ , simultaneously from the top of a tower of height H. If the body reaches the highest point before the dropped body reaches the ground, then maximum height reached by the center of mass of the system from ground is
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a
H+u22g
b
u22g
c
H+12gMuM+m2
d
H+12gmuM+m2
answer is C.
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Detailed Solution
Initial position of center of mass from the ground is =HInitial velocity of center of mass v=0+MuM+mmaximum height attained by center of mass =v22g=MuM+m212gHeight from the ground=H+MuM+m212g
A body of mass ‘m’ is dropped and another body of mass M is projected vertically up with speed ‘u’ , simultaneously from the top of a tower of height H. If the body reaches the highest point before the dropped body reaches the ground, then maximum height reached by the center of mass of the system from ground is