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A body of mass m is kept on a rough horizontal surface (coefficient of friction = μ). A horizontal force is applied on the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by F, where F is,

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a

|F→|=mg

b

|F→|=mg+μmg

c

|F→|=μmg

d

|F→|≤mg1+μ2

answer is D.

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Detailed Solution

Since body does not move hence it is in equilibrium.fr = frictional force which is less than or equal to limiting friction.Now N = mg Hence F→=N→+f→r |F→|≤(mg)2+(μmg)2 |F→|≤mg1+μ2

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A body of mass m is kept on a rough horizontal surface (coefficient of friction = μ). A horizontal force is applied on the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by F, where F is,