A body A, of mass m= 0.1kg has an initial velocity of 3i∧ms−1 . It collides elastically with another body, B of the same mass which has an initial velocity of 5j∧ms−1 . After collision, A moves with a velocity v→=4i∧+j∧ . The energy of B after collision is written as x10J . the value of x is _________

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answer is 0001.00.

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Detailed Solution

Since collision is elastic , initial K.E.= final K.E ⇒120.19+120.125=120.142+422+K.EB ⇒K.EB=120.134−32 =0.1 J So, X10=0.1 ⇒X=1

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