Q.

A body of mass m kg. starts falling from a point  2R above the Earth’s surface. Its kinetic energy when it has fallen to a point ‘R’ above the Earth’s surface [R-Radius of Earth, M-Mass of Earth, G-Gravitational Constant]

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a

12GMmR

b

16GMmR

c

23GMmR

d

13GMmR

answer is B.

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Detailed Solution

Potential energy U=−GMmr=−GMmR+hUini​​tial=−GMm3R and Ufinal=−−GMm2RLoss in PE = gain in KE=GMm2R−GMm3R=GMm6R
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A body of mass m kg. starts falling from a point  2R above the Earth’s surface. Its kinetic energy when it has fallen to a point ‘R’ above the Earth’s surface [R-Radius of Earth, M-Mass of Earth, G-Gravitational Constant]