A body of mass m kg. starts falling from a point 2R above the Earth’s surface. Its kinetic energy when it has fallen to a point ‘R’ above the Earth’s surface [R-Radius of Earth, M-Mass of Earth, G-Gravitational Constant]
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a
12GMmR
b
16GMmR
c
23GMmR
d
13GMmR
answer is B.
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Detailed Solution
Potential energy U=−GMmr=−GMmR+hUinitial=−GMm3R and Ufinal=−−GMm2RLoss in PE = gain in KE=GMm2R−GMm3R=GMm6R