A body of mass m kg starts falling from a point 2R above the Earth's surface. Its kinetic energy when it has fallen to a point R above the Earth's surface [R: Radius of Earth, M:Mass of Earth, G: Gravitational Constant]
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a
12GMmR
b
16GMmR
c
23GMmR
d
13GMmR
answer is B.
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Detailed Solution
Potential energy, U=−GMmr=−GMmR+hUinitial =−GMm3R and Ufinal =−−GMm2R Loss in PE= gain in KE=GMm2R−GMm3R=GMm6R