A body of mass m is moving in a circle of radius r with a constant speed v. The force on the body is mv2r and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle

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mv2πr2

Zero

mv2r2

πr2mv2

answer is B.

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Detailed Solution

Work done by centripetal force is always zero, because force and instantaneous displacement are always perpendicular.W=F→.s→=Fscosθ=Fscos(90°)=0

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