First slide

The steps in collision

Question

Body A of mass 4m moving with speed u collides with another body B of mass 2m, at rest . The collision is head on and elastic in nature. After the collision the fraction of energy lost of the colliding body A is:

Moderate

A

4/9
B

5/9
C

1/9
D

8/9

Solution

Fractional loss of KE colliding body
$\large \frac{{\Delta KE}}{{KE}} = \frac{4(m_1m_2)}{(m_1+m_2)^2}\\\\=\frac{4(4m)2m}{(4m+2m)^2}\\\\=\frac{32m^2}{36m^2}=\frac{8}{9}$

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