First slide

Gravitaional potential energy

Question

A body of mass m is placed on earth surface which is taken from earth surface to a height of h = 3R, then change in gravitational potential energy is :

Easy

A

$\frac{mgR}{4}$
B

$\frac{2 mgR}{3}$
C

$\frac{3 mgR}{4}$
D

$\frac{mgR}{2}$

Solution

change in gravitational PE $= - \frac{GMm}{4 R} - (- \frac{GMm}{R})$
$= \frac{3}{4} \frac{GMm}{R} = \frac{3}{4} mgR$

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