Q.

A body of mass m is placed on the earth’s surface. It is taken from the earth’s surface to a height  h = 3R. The change in gravitational potential energy of the body is

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a

23mgR

b

34mgR

c

mgR2

d

mgR4

answer is B.

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Detailed Solution

ΔU=mgh1+hR=mg×3R1+3RR=34mgR
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