Q.
A body of mass m is placed on the earth’s surface. It is taken from the earth’s surface to a height h = 3R. The change in gravitational potential energy of the body is
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a
23mgR
b
34mgR
c
mgR2
d
mgR4
answer is B.
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Detailed Solution
ΔU=mgh1+hR=mg×3R1+3RR=34mgR
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