Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A body of mass m is placed on a rough surface with coefficient of friction μ inclined at θ. If the mass is in equilibrium, then

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

θ  = tan-1μ

b

θ  = tan-11μ

c

θ  = tan-1mμ

d

θ  = tan-1μm

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Consider a body of mass m placed on a rough inclined surface and it is just on the point of sliding down, with coefficient of friction μ inclined at angle θ, as shown in figure.At the equilibrium point O,In case of limiting condition, F = mg sin θ       …….(i)Normal force, R = mg cos θ            …….(ii)On dividing Eq. (i) by Eq. (ii), we getFR  = mg sinθmg cosθμ = tanθ                      (∵ Force of friction, F = μR)⇒  θ  = tan-1(μ)This is maximum value of θ for mass m to be at rest.For smaller θ, body will be at rest, i.e. in equilibrium.So, angle of repose, i.e. θ  = tan-1μ
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
A body of mass m is placed on a rough surface with coefficient of friction μ inclined at θ. If the mass is in equilibrium, then