A body of mass m is projected horizontally with a velocity v from the top of a tower of height h and it reaches the ground at a distance x from the foot of the tower. If a second body of mass $$2m$$ is projected horizontally from the top of a tower of height $$2$$ h, it reaches the ground at a distance $$2$$ x from the foot of the tower. The horizontal velocity of second body is

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Infinity Learn · Accepted Answer

For first body,       $$h=12gt2$$      …(1)and$$    x $$=$$ vt         ….. $$(2)From$$ eqs. $$(1) and (2),     $$h=12gx2/v2$$          ….(3)For$$ second body, let v' be the velocity of projection, $$then2h=12g(2x)2v$$′$$2$$      …. $$(4)Dividing$$ eq. $$(3) by eq. (4), we $$get12=x2v2$$×v′$$24x2$$  or  v′$$=2$$⋅v

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