First slide
Projection Under uniform Acceleration
Question

A body of mass m is projected horizontally with a velocity v from the top of a tower of height h and it reaches the ground at a distance x from the foot of the tower. If a second body of mass 2 m is projected horizontally from the top of a tower of height 2 h, it reaches the ground at a distance 2x from the foot of the tower. The horizontal velocity of the second body is

Moderate
Solution

x=v2hg,2x=v'2(2h)g Solvetoget v'=2v

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