A body of mass m is projected with a velocity u at an angle of 60º with the horizontal. The magnitude of the angular momentum about the point of projection when the body is at the highest point of its trajectory is
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a
mu32g
b
2mu35g
c
3mu316g
d
mu34g
answer is C.
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Detailed Solution
At highest pointv=ucos60∘=u2Hence at maximum height perpendicular distance from line of projection =u2sin2θ2g=3u28gL=mvr=mucos60∘×3u28g=3mu316g