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A body of mass m is projected with vertical making an angle 45o with the horizontal from the point P. Its highest point is H and it returns to the ground at Q. The change in angular momentum in going from P to Q is

a
4mv3g
b
3mv3g
c
mv32g
d
mv342g

detailed solution

Correct option is C

|ΔL|=LQ−LP. Here LP=0∴ ΔL=LQ=r×p=R×pwhere r = R = rangeAt an angle of 45∘R=V2g and p=musin⁡45∘=mu2∴ ΔL=V2g×mv2=mv32g

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