A body of mass m and radius r is released from rest along a smooth inclined plane of angle of inclination θ. The angular momentum of the body about the instantaneous point of contact after a time t from the instant of release is equal to:
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
mgrt cosθ
b
mgrt sinθ
c
(32)mgrt sinθ
d
none of these
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Since the surface is frictionless, the body does not rotate about its centre of mass. Only it slides parallel to the surface. i.e. ω = 0 and v = (g sin θ)tThe angular momentum after time t:L = mvr = m(g sin θ)tr = mgrt sinθ