A body of mass m is raised to a height  10R from the surface of the earth, where R is the radius of the earth. The increase in potential energy is (G = universal constant of gravitation, M = mass of the earth and g = acceleration due to gravity) [MHT CET 2014]

Potential energy at the earth surface   =-GMmRPotential energy at a height h above the earth's surface=-GMm(R+h)                             …(i)∴   Change m' potential energy,  ΔPE=-GMm(R+h)--GMmR                                                              =G↑MmhR(R+h)              …(ii)Substituting the value of h = 10R in Eq. (i), we getΔPE=GMm×10RR(R+10R)=10GMm11R