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Q.

A body of mass M at rest explodes into three pieces, two of which of mass M4 each are thrown off in perpendicular directions with velocities of 3 m/s and 4 m/s  respectively. The third piece will be thrown off with a velocity of

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a

1.5 m/s

b

2.0 m/s

c

2.5 m/s

d

3.0 m/s

answer is C.

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Detailed Solution

Momentum of one piece = M4×3Momentum of the other piece = M4 × 4Resultant momentum = 9M216+M2 = 5M4The third piece should also have the same momentum. Let its velocity be v, then5M4 = M2×v or v = 52 = 2.5 m/sec
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A body of mass M at rest explodes into three pieces, two of which of mass M4 each are thrown off in perpendicular directions with velocities of 3 m/s and 4 m/s  respectively. The third piece will be thrown off with a velocity of