A body of mass M at rest explodes into three pieces, two of which of mass $$M4$$ each are thrown off in perpendicular directions with velocities of $$3$$ $$m/s$$ and $$4$$ $$m/s$$ respectively. The third piece will be thrown off with a velocity of

Question

A body of mass M at rest explodes into three pieces, two of which of mass $$M4$$ each are thrown off in perpendicular directions with velocities of $$3$$ $$m/s$$ and $$4$$ $$m/s$$  respectively. The third piece will be thrown off with a velocity of

Infinity Learn · Accepted Answer

Momentum of one piece $$=$$ $$M4$$×$$3Momentum$$ of the other piece $$=$$ $$M4$$ × $$4Resultant$$ momentum $$=$$ $$9M216+M2$$ $$=$$ $$5M4The$$ third piece should also have the same momentum. Let its velocity be v, $$then5M4$$ $$=$$ $$M2$$×v or v $$=$$ $$52$$ $$=$$ $$2.5$$ $$m/$$$$sec$$

A body of mass M at rest explodes into three pieces, two of which of mass $\frac{M}{4}$ each are thrown off in perpendicular directions with velocities of 3 m/s and 4 m/s respectively. The third piece will be thrown off with a velocity of

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A body of mass M at rest explodes into three pieces, two of which of mass M4 each are thrown off in perpendicular directions with velocities of 3 m/s and 4 m/s respectively. The third piece will be thrown off with a velocity of

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A body of mass M at rest explodes into three pieces, two of which of mass $\frac{M}{4}$ each are thrown off in perpendicular directions with velocities of 3 m/s and 4 m/s respectively. The third piece will be thrown off with a velocity of