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A body of mass m rises to height h =R/ 5 from the earth's surface, where R is earth's radius. If g is acceleration due to gravity at earth's surface, the increase in potential energy is

a
mgh
b
(4/5) mgh
c
(5/6) mgh
d
(6/7) mgh

detailed solution

Correct option is C

ΔV=GMmR−GMmR+(R/5)=GMm6R=GMR2×mR6=mgR6 ∵GMR2=g=mg(5h)6=56mgh

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