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Q.

A body of mass m rises to height h =R/ 5 from the earth's surface, where R is earth's radius. If g is acceleration due to gravity at earth's surface, the increase in potential energy is

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a

mgh

b

(4/5) mgh

c

(5/6) mgh

d

(6/7) mgh

answer is C.

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Detailed Solution

ΔV=GMmR−GMmR+(R/5)=GMm6R=GMR2×mR6=mgR6 ∵GMR2=g=mg(5h)6=56mgh
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A body of mass m rises to height h =R/ 5 from the earth's surface, where R is earth's radius. If g is acceleration due to gravity at earth's surface, the increase in potential energy is