A body of mass m rises to height h = R/5 from the earth's surface, where R is earth's radius. If g is acceleration due to gravity at earth's surface, the increase in potential energy is

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mgh

45mgh

56mgh

67mgh

answer is C.

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Detailed Solution

ΔU=mgh1+h/R Substituting R=5h we get ΔU=mgh1+1/5=mgh5+15=56mgh

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