Q.
A body of mass 'm' is taken from the earth's surface to the height equal to twice the radius (R) of the earth. The change in potential energy of body will be
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a
3mgR
b
13mgR
c
mg2R
d
23mgR
answer is D.
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Detailed Solution
Gravitational potential energy at any point at a distance r from the centre of the earth isU=−GMmrwhere M and m be masses of the earth and the body respectively.At the surface of the earth, r = R∴ Ui=GMmRAt a height h from the surface.r=R+h=R+2R ∵h=2RGiven= 3R∴ Uf=GMm3RChange in potential energy,ΔU=Uf−Ui =−GMm3R−−GMmR =GMmR1−13=23GMmR =23mgR ∵g=GMR2
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