Question

A body of mass m is thrown upwards at an angle $θ$ with the horizontal with velocity v. While rising up the velocity of the mass after t seconds will be

Moderate

Solution

Instantaneous velocity of rising mass after t second will be
$v_{t} = \sqrt{{v_{x}}^{2} + {v_{y}}^{2}}$
where, v_x = v cos $θ$ = horizontal component of velocity
v_y = v sin $θ$ $-$ gt = vertical component of velocity.
$\Rightarrow v_{t} = \sqrt{(v \cos θ)^{2} + (v \sin θ - g t)^{2}}$
$\Rightarrow v_{t} = \sqrt{v^{2} + g^{2} t^{2} - (2 v \sin θ) g t}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

SCAN ME