A body of mass m is thrown upwards at an angle θ with the horizontal with velocity v. While rising up the velocity of the mass after t seconds will be

Instantaneous velocity of rising mass after t second will bevt = vx2 + vy2where, vx = v cos θ = horizontal component of velocityvy = v sin θ - gt = vertical component of velocity.⇒ vt=(vcosθ)2+(vsinθ-gt)2⇒  vt=v2+g2t2-(2vsinθ)gt