Questions
A body of mass m is thrown upwards at an angle with the horizontal with velocity v. While rising up the velocity of the mass after t seconds will be
detailed solution
Correct option is C
Instantaneous velocity of rising mass after t second will bevt = vx2 + vy2where, vx = v cos θ = horizontal component of velocityvy = v sin θ - gt = vertical component of velocity.⇒ vt=(vcosθ)2+(vsinθ-gt)2⇒ vt=v2+g2t2-(2vsinθ)gtTalk to our academic expert!
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