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Q.

A body is moving from rest under constant acceleration and let S1 be the displacement in the first (p-1) sec and S2 be the displacement in the first p sec. The displacement in (p2-p+1)th sec. will be

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a

S1 +S2

b

S1S2

c

S1-S2

d

S1/S2

answer is A.

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Detailed Solution

From S = ut + 12at2S1 = 12a(P-1)2 and S2 = 12a P2   [As u = 0]From Sn = u+a2(2n-1)S(P2-P+1)th = a2[2(P2-P+1)-1]                          = a2[2P2-2P+1]It is clear that S(P2-P+1)th= S1+S2
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