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Q.

A body, moving in a straight line with an initial velocity of 5 ms-1 and a constant acceleration, covers a distance of 30 m in the 3rd second. How much distance (in m) will it cover in the next 2 seconds?

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answer is 90.

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Detailed Solution

Now, sn=u+an−12, Therefore, 30=5+a3−12which gives a=10 ms−2.∴s4=5+104−12=40 m and s5=5+105−12=50 m∴s=s4+s5=40+50=90 m
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