First slide

Rectilinear Motion

Question

A body, moving in a straight line with an initial velocity of 5 ms^-1 and a constant acceleration, covers a distance of 30 m in the 3^rd second. How much distance (in m) will it cover in the next 2 seconds?

Moderate

Solution

Now, $s_{n} = u + a (n - \frac{1}{2})$ , Therefore, $30 = 5 + a (3 - \frac{1}{2})$
which gives $a = 10 {ms}^{- 2}$ .
$∴ s_{4} = 5 + 10 (4 - \frac{1}{2}) = 40 m$ and $s_{5} = 5 + 10 (5 - \frac{1}{2}) = 50 m$
$∴ s = s_{4} + s_{5} = 40 + 50 = 90 m$

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