A body moving with uniform acceleration covers 100m in the first 10s and 150m in the next  10s. The acceleration of the body is

Let ‘u’ and ‘a’ be the initial velocity and acceleration of the body respectively
$\therefore$ From equation  $S=ut+\frac{1}{2}a{t}^2$
Step-I
$100=10u+\frac{1}{2}a{\left(10\right)}^2$ 
$\Rightarrow 10=u+5a\mathrm{..........}\left(1\right)$ 
Step-II
The total distance covered in the total time of 20S is 100+150=250m 
$\therefore 250=20u+\frac{1}{2}a{\left(20\right)}^2$ 
$\Rightarrow 250=20u+200a$ 
$\Rightarrow 25=2u+20a\mathrm{........}\left(2\right)$ 
On solving equations (1) & (2)
Acceleration  $a=0.5m/s^2$