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For a body moving with uniform acceleration ‘a,’ initial and final velocities in a time interval ‘t’ are ‘u’ and ‘v’ respectively. Then its average velocity in the time interval ‘t’ in terms of v,a,t is

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a

v+at

b

v−at2

c

v−at

d

u−at2

answer is B.

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Detailed Solution

average velocity of v1 & v2 is v1+v22 Average velocity of u & v =u+v2---(1) From kinetic equation→v=u+at; u=v−at---(2)substitute equation (2) in (1)vaverage=v−at+v2vaverage=2v2−at2vaverage=v−at2

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For a body moving with uniform acceleration ‘a,’ initial and final velocities in a time interval ‘t’ are ‘u’ and ‘v’ respectively. Then its average velocity in the time interval ‘t’ in terms of v,a,t is