First slide

Different question variety formed

Question

A body moving with uniform retardation covers 3 km before its speed is reduced to half. It comes to rest after travelling a distance of

Easy

A

1 km
B

2 km
C

3 km
D

4 km

Solution

$v^{2} - {(\frac{v}{2})}^{2} = 2 \times 3 \times a$
$\Rightarrow {(\frac{v}{2})}^{2} - 0 = 2 \times S \times a$
Solving S = 1 km.

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