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Q.

A body is moving with uniform velocity of 8 ms-1. When the body just crossed another body, the second one starts and moves with uniform acceleration of 4 ms-2. The distance covered by the second body when they meet is:

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a

8 m

b

16 m

c

24 m

d

32 m

answer is D.

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Detailed Solution

Srel=Urelt +12arelt20=-8t+124t2t=2 sdistance covered before meeting s = 8t = 8×4 = 32 m
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