Questions
A body is oscillating simple harmonically with a period T = 2 s. How much time would it take for its kinetic energy to decrease from to 75 % of ?
detailed solution
Correct option is D
K=12mv2=m2A2ω2cos2(ωt) and Kmax=mA2ω22 Given that K=0.75Kmax⇒cos(ωt)=32⇒ωt=π6⇒2πTt=π6. Simplifying this we get t=T12=212=16sTalk to our academic expert!
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