First slide

Types of collision

Question

A body P of mass 2m moving with velocity u collides head-on with a stationary body Q of mass m. After the collision, the bodies coalesce. Then percentage loss of energy of P in the process is

Easy

A

24.42%
B

55.55%
C

40.58%
D

62.18%

Solution

Conserving momentum, $(2 m + m) V = 2 m . u \Rightarrow V = \frac{2 u}{3}$
Energy lost $= \frac{\frac{1}{2} .2 m . u^{2} - \frac{1}{2} .2 m . V^{2}}{\frac{1}{2} .2 m . u^{2}} \times 100 % = 55.55 %$

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