First slide

Projection Under uniform Acceleration

Question

A body is projected at angle 30⁰ to horizontal with a velocity 50 ms^–1. Its time of flight is (g=10 m/s²)

Easy

A

4 s
B

5 s
C

6 s
D

7 s

Solution

Time of flight $T = \frac{2 Usin θ}{g}$
$= \frac{2 \times 50}{10} \times \frac{1}{2}$
= 5 sec

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